By means of Eqs. 5.6 and 5.7 and the formula for shear stress in a beam of rectangular cro...

By means of Eqs. 5.6 and 5.7 and the formula for shear stress in a beam of rectangular cross section given in Problem 5.4, show that the correction coefficient k (see Eq. 5.14) is 1.20.

 (5.6)

 (5.7)

Problem 5.4

The shear stress distribution in a beam of rectangular cross section (Figure P5.4) subjected to shear force Vy is given by

Show that the shear stress is, as a function of y,

where τmax = 3Vy/2A and A is the cross-sectional area. Hence, show that the shear stress varies parabolically and is a maximum at y = 0.

FIGURE P5.4

 (5.14)