Calculate the volume of 0.0500 M EDTA needed to titrate
*(a) 29.13 mL of 0.0598 M Mg(NO3)2.
(b) the Ca in 0.1598 g of CaCO3.
*(c) the Ca in a 0.4861-g mineral specimen that is 81.4% brushite, CaHPO4.2H2O (172.09 g/mol).
(d) the Mg in a 0.1795-g sample of the mineral hydromagnesite, 3MgCO3Mg(OH)2.3H2O (365.3 g/mol).
*(e) the Ca and Mg in a 0.1612-g sample that is 92.5% dolomite, CaCO3.MgCO3 (184.4
g/mol).
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