Using these three formulas
V = IR
R = (ρL)/A
A = π(0.5d)2
find the difference in current (I) that a copper wire (ρ = 1.72 × 10−8 Ω · m) can carry over an aluminum wire (ρ = 2.75 × 10−8 Ω · m) with equal diameters (d) of 0.5 cm and a length (L) of 10 000 m carrying 110 V (volts).
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