In Problem, use elementary row operations to transform each augmented coefficient matrix to echelon form. Then solve the system by back substitution.
4x1 − 2x2 − 3x3 + x4 = 3
2x1 − 2x2 − 5x3 = −10
4x1 + x2 + 2x3 + x4 = 17
3x1 + x3 + x4 = 12
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