Solutions For Digital Design Chapter 2 Problem 2PE

Design a truth table for the expression, with F as output.

The following table shows the truth table of the function, .

Note that the function \(F\) is high only when \(x=0, y=0\), and \(z=1\), because the function is AND operation of negation of \(x\), negation of \(y\) with \(z\) that is, \(F=x^{\prime} y^{\prime} z\).

Therefore, the truth table for the Boolean expression is shown in Table 1 .