In Problem, use elementary row operations to transform each augmented coefficient matrix to echelon form. Then solve the system by back substitution.
x1 + x2 + x3 + = 6
2x1 − 2x2 − 5x3 = −13
3x1 + x3 + x4 = 13
4x1 − 2x2 − 3x3 + x4 = 1
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