To derive (17) from (10), we argued that l/T(K −n+1) = 0 for k = 0,1,..., n − 1, on the gr...

To derive (17) from (10), we argued that l/T(K −n+1) = 0 for k = 0,1,..., n − 1, on the grounds that for those k’s T(k − n + 1) is infinite. However, while it is true that the gamma function becomes infinite as its argument approaches 0, −1, −2,..., it is not rigorous to say that it is infinite at those points; it is simply undefined there. Here, we ask you to verify that the k = 0,1,..., n −1 terms are zero so that the correct lower limit in (17) is, indeed, k = n. For definiteness, let v = 3 and r = −v = − 3. (You should then be able to generalize the result for the case of any positive integer v, but we do not ask y;ou to do that; v = 3 will suffice.) HINT: Rather than work from (17), go back to the formulas (4a,b,c).