Problem

The spring constant k = 700 N/m. The masses mA = 14 kg and mB = 18 kg. The horizontal bar...

The spring constant k = 700 N/m. The masses mA = 14 kg and mB = 18 kg. The horizontal bar is smooth. At the instant shown, the spring is unstretched and the mass B is moving downward at 1 m/s. How fast is B moving when it has moved downward 0.2 m from its present position?

Step-by-Step Solution

Solution 1

Given data:

Spring constant of the spring,

Masses of the collar and block are and respectively

Initial velocity of the block B,

The displacement of the block B,

Let V be the velocity of collar and block in its final position.

The initial and final positions of the system are as shown in the figure

The stretch in the spring can be obtained from the following figure

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When block moves 0.2 m downward, collar ‘A’ slides 0.2 m in horizontal direction and we have

The change in length of the spring (as the spring is initially un-stretched) is given by

Using conservation of energy for the system at positions 1 and 2, we get

Solving for the velocity, we get

Thus, the velocity of the block after the initial displacement is equal to

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