The total external force on the 10-kg object shown in Problem is given as a function of ti...
The total external force on the 10-kg object shown in Problem is given as a function of time by ΣF = (–20t + 90)i – 60j + (10t + 40)k (N). At time t = 0, its position is r = 40i + 30j – 360k (m) and its velocity is v = –14i + 26j + 32k (m/s). What is its position at t = 4s?
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Solutions For Problems in Chapter 14
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