Treatment of hydroxylamine (H2NOH) with an excess of Fe(III) results in the formation of N2O and an equivalent amount of Fe(II): 2H2NOH + 4Fe3+ → N2O(g) + 4Fe2+ + 4H+ + H2O Calculate the molar concentration of an H2NOH solution if the Fe(II) produced by treatment of a 25.00-mL aliquot required 14.48 mL of 0.01528 MK2Cr2O7.
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