Let P be any point in the interior of circle O except O itself. Show that the shortest chord containing P must be the one where is perpendicular to the chord.
(Hint: Draw chord where P is on and is perpendicular to . Then draw any other chord through point P. Then consider the perpendicular segment from O to .)
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.