Material is the same as for Problem 1, namely σult = 90,000 psi and σe = 40,000 psi for a ground surface. At the point of expected failure K = 1.5. The loading is as follows:
σavg = 21,000 psi, | σr = 21,300 psi, | for 36% of the time |
σavg = 39,000 psi, | σr = 15,480 psi, | for 49% of the time |
σavg = 31,000psi, | σr = 20,850 psi, | for 15% of the time |
(a) Find the equivalent completely reversed stresses for each stress.
(b) Find the life if each stress only would be applied and find the expected overall life N.
Problem 1
A steel has a tensile strength of 90,000 psi and an endurance limit of 40,000 psi when the surface is ground.
(a) Find the value of constants A and B for Basquin’s equation.
(b) For a loading of σavg = 27,050 psi and σr = 20,020 psi and a stress concentration factor 1.5, find the value of σr, the equivalent completely reversed stress.
(c) For the loading of part (b), calculate the expected number of reversals to failure.
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