Considering Section 7.1, suppose we began the analysis to find E = E1 + E2 with two cosine functions E1 = E01 cos (ωt + α1) and E2 = E02 cos (ωt + α2). To make things a little less complicated, let E01 — E02 and α1 =0. Add the two waves algebraically and make use of the familiar trigonometric identity cos θ + cos φ=2 cos ½(θ + φ) cos ½(θ-Ф) in order to show that E = E1 cos (ωt + α), where E0=2 E01 cos α2/2 and α = α2/2. Now show that these same results follow from Eqs. (7.9) and (7.10).
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