Problem

The allowed rotational energies of a diatomic molecule are given by In this expression l...

The allowed rotational energies of a diatomic molecule are given by

In this expression l is the rotational quantum number and can take the values l = 0, 1, 2 …; I is the rotational inertia of the molecule about an axis through its center of mass; and ℏ= h/2π. The equilibrium separation of the two atoms in a diatomic hydrogen molecule H2 is about 0.074 nm. The mass of each hydrogen atom is about 1.67 × 10−27 kg.

a. Show that the rotational inertia of the hydrogen molecule about an axis through its center of mass is about I =4.6× 10−48 kg · m2.


b. Find the difference in energy between the first excited rotational energy stale and the ground rotational state. That is, find . Express the answer in both J and eV.


c. Find the relative likelihood Pl = 1/Pl = 0 that a hydrogen molecule will be in its first excited rotational state in thermal equilibrium at room temperature, T = 293 K. (Ignore possible state degeneracies.)

Step-by-Step Solution

Request Professional Solution

Request Solution!

We need at least 10 more requests to produce the solution.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the solution will be notified once they are available.
Add your Solution
Textbook Solutions and Answers Search
Solutions For Problems in Chapter 6