Suppose the horizontal reducing bend in example 4.4.2 has an unknown bend angle (45° in example 4.4.2). What should be this bend angle so that the horizontal component force Fx is three times the vertical component force, Fy, in magnitude?
EXAMPLE 4.4.2
Water flows through a horizontal 45° reducing bend shown in Figure 4.4.3, with a 36-in diameter upstream and a 24-in diameter downstream, at the rate of 20 cfs under a pressure of 15 psi at the upstream end of the bend. Neglecting the headloss in the bend, calculate the force exerted by the water on the bend.
SOLUTION
The free-body diagram shown in Figure 4.4.3 is used. To solve this problem, equations (4.4.3) and (4.4.4) will be used:
The first objective is to determine the velocities in order to apply the energy equation to determine p2:
Next the energy equation is applied horizontally, z1 = z2 = 0 and hL = 0:
Using equation (4.4.3) yields
Using equation (4.4.4), we get
where Fy1 = 0 because there is no pressure component in the y direction at 1.
The resultant force is at an angle of θ = tan−1(4901/8517) = 30°.
Figure 4.4.3 Reducing bend for example 4.4.2.
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