Suppose the block matrix A on the left side of (7) is invertible and A11 is invertible. Show that the Schur complement S of A11 is invertible. [Hint: The outside factors on the right side of (7) are always invertible. Verify this.] When A and A11 are both invertible, (7) leads to a formula for A–1, using S–1, , and the other entries in A.
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.