Determine the minimum sample size required when you want to be 90% confident that the sample mean is within one unit of the population mean and
sigma=19.8. Assume the population is normally distributed.
A 90 % confidence level requires a sample size of?
Solution:
Population standard deviation = 19.8
Margin of error = 1
Alpha =0.1
Alpha/2 =0.05, Zalpha/2 = 1.96
Margin of error = Zalpha/2*SD/sqrt(n)
1 = 1.96*19.8/sqrt(n)
n =(1.96*19.8)^2 = 1506
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