Question

Assume that when adults with smartphones are randomly selected, 53% use them in meetings or classes. If 5 adult smartphone users are randomly selected, find the probability that exactly 3 of them use their smartphones in meetings or classes

Answer 1

Solution

Given that ,

p = 53% = 0.53

1 - p = 1 - 0.53 = 0.47

n = 5

x = 3

Using binomial probability formula ,

P(X = x) = ((n! / x! (n - x)!) * p^x * (1 - p)^{n - x}

P(X = 3) = ((5! / 3! (5 - 3)!) * 0.53³ * (0.47)^{5 - 3}

=  ((5! / 3! (2)!) * 0.53³ * (0.47)²

= 0.3289

Probability = 0.3289