If two dice are thrown, what is the probability that the sum is (a) greater than 8 ? (b) neither 7 nor 11 ?
A) cases with sum greater than 8 = {(3,6) (4,5) (4,6) (5,4) (5,5) (5,6) (6,3) (6,4) (6,5) (6,6) }= 10 outcomes
Total outcomes = 36
Probability sum greater than 8 = 10/36 = 5/18
B) sum 7 ={(1,6) (2,5) (3,4) (4,3) (5,2) (6,1) } =6 outcomes
Sum 11 = {(5,6) (6,5)} = 2 outcomes
Probability sum neither 7 nor 11 = (36 - 6 -2)/36 = 28/36 = 7/9
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