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If two dice are thrown, what is the probability that the sum is (a) greater than...

If two dice are thrown, what is the probability that the sum is (a) greater than 8 ? (b) neither 7 nor 11 ?

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Answer #1

A) cases with sum greater than 8 = {(3,6) (4,5) (4,6) (5,4) (5,5) (5,6) (6,3) (6,4) (6,5) (6,6) }= 10 outcomes

Total outcomes = 36

Probability sum greater than 8 = 10/36 = 5/18

B) sum 7 ={(1,6) (2,5) (3,4) (4,3) (5,2) (6,1) } =6 outcomes

Sum 11 = {(5,6) (6,5)} = 2 outcomes

Probability sum neither 7 nor 11 = (36 - 6 -2)/36 = 28/36 = 7/9

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