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Complete parts​ (a) and​ (b) below. The number of dogs per household in a small town Dogs: 0 1 2 3 4 5 Probability: 0...

Complete parts​ (a) and​ (b) below. The number of dogs per household in a small town

Dogs: 0 1 2 3 4 5

Probability: 0.677 0.203 0.079 0.023 0.013 0.005

​(a) Find the​ mean, variance, and standard deviation of the probability distribution. Find the mean of the probability distribution.

μ=

​(Round to one decimal place as​ needed.)

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Answer #1
Concepts and reason

The probability is defined as the measure of the likelihood that an event will occur. The probability value is always lies between 0 and 1.

Probability distribution assigns a probability value to each of the possible value of a random variable.

Fundamentals

The formula for the calculating the expected value of x is,

(s)=(x)

The formula for the variance of the probability distribution is,

v(x)={x?P(x)-[E(X)]

The formula for the standard deviation of X is,

o=JV(x)

From the information, observe that following probability distribution.

X 0 1 2 3 4 5 Total
P(x) 0.677 0.203 0.079 0.023 0.013 0.005 1.000

The calculation of the mean is,

E(X)-ΣπP(x)
(0x0.677) + (1x0.203) + (2x0.079) +)
T(3x 0.023)+ (4x 0.013)+(5x 0.005) )
= {0 + 0.203 + 0.158 + 0.069 + 0.052 +

The calculation of the variance is,

V(x)={x?P(x)-[E(x)]
[ſ(oʻx0.677)+(12 x0.203) +(22 x 0.079)+1].
}|-[0.507]
N|(32x0.023)+(4+ x 0.013)+(52x0.005) SI
={0+0.203+0

The calculation of the required standard deviation is,

o= V(X)
= V0.8020
= 0.896

Ans:

The calculated value of the expected value for the given probability distribution is 0.507

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