Question

A model rocket is launched straight up from ground level with an initial velocity of 96 feet per second. Its height, in feet, after t seconds is given by the equation 2 s t t t ( ) 16 96    . a. What is the model rocket’s maximum height and when in its flight does it reach this point? b. At what time(s) will it reach a height of 80 feet? c. After how many seconds will it return to the ground? Question(s) a., b., and c. should also be answered in sentence form. In addition to showing the calculations that lead to your solution, write a synopsis of the tactic(s) you used to arrive at your solution(s) to this series of questions. Use clear and concise vocabulary, sentence structure, and grammar. Your answer should be labelled with appropriate units and reflect the context used in this question.

Answer 1

Given, s(t) = -167 +967 height velocity and velocity = de At maximum velocity is o de Vods - 32+ +96=0 dt Maximum height => tage see = 3 422 = SL4) - 96x3 – 16x9 = 144H) 128 feett Answer 5 To reach height 80 feet 80 = -16+2 + 96t - 16t²-96t+80=0 - t²_6t 45=0 -> t = 5,1 t=1 second and s second rockeet will reach &o feets s(t)=0 wh So -16? +96=0 16 sec 76 so, at 2 71 16+ = 96 ) t = 96 height is reached at 3 sec and is @ In sentence fom Maximum T1446 ① Rocket will reach 80 ft at 1 see and 5 see Rocket will reach again at ground in 16 sec

e Tactics used when is reached @ Maximum height Velocity velocity is zero- is diffrential as rate of Change of displacement bi using equation of equaticang Slt.) = 80 © At ground displacement is zero.