A model rocket is launched straight up from ground level with an initial velocity of 96...
A model rocket is launched straight up from ground level with an initial velocity of 96 feet per second. Its height, in feet, after t seconds is given by the equation s(t)=-16t2+96t. At what time(s) will it reach a height of 80 feet? b. After how many seconds will it return to the ground? Question(s) a. and b. should also be answered in sentence form. In addition to showing the calculations that lead to your solution, write a synopsis of the tactic(s) you used to arrive at your solution(s) to this series of questions. Use clear and concise sentence structure and grammar. Your answer should be labelled with appropriate units and reflect the context used in this question.
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A model rocket is launched straight up from ground level with an
initial velocity of 96...
A model rocket is launched straight up from ground level with an initial velocity of 96...
A model rocket is launched straight up from ground level with an initial velocity of 96 feet per second. Its height, in feet, after t seconds is given by the equation 2 s t t t ( ) 16 96 . a. What is the model rocket’s maximum height and when in its flight does it reach this point? b. At what time(s) will it reach a height of 80 feet? c. After how many seconds will...
A projectile is launched straight up from ground level with an initial velocity of v0 per...
A projectile is launched straight up from ground level with an initial velocity of v0 per sec. Neglecting air resistance, its height in feet, s, after t seconds after launch is given by the equation s = –16t2 + v0t. At what time(s) will the projectile reach a height of 112 feet when v0 = 96 feet/sec? After how many seconds will it return to the ground when v0 = 96 feet/sec?
A toy rocket is launched upward with an initial velocity of 64ft/s from a platform that...
A toy rocket is launched upward with an initial velocity of 64ft/s from a platform that is 80ft. above the ground. The acceleration of the rocket is a(t) = -32ft. Find the height of the rocket after t seconds. When does it hit the ground? Use calculus methods to solve the problem.
A projectile is launched from ground level with an initial velocity of v 0 feet per...
A projectile is launched from ground level with an initial velocity of v 0 feet per second. Neglecting air? resistance, its height in feet t seconds after launch is given by s equals negative 16 t squared plus v 0 t. Find the? time(s) that the projectile will? (a) reach a height of 80 ft and? (b) return to the ground when v 0 is 32 feet per second. ?(a) Find the? time(s) that the projectile will reach a height...
by matlab programm please 3. A rocket is launched straight into the air with initial velocity...
by matlab programm please
3. A rocket is launched straight into the air with initial velocity 200 ft/s. Assume the launch is instantaneous. How high will it go, and how long will that take (use time increments of 0.01 seconds)? G-- 32.2 ft/s, Ho-0 (the ground) V(t)-Vo+ g t H(t) Ho+ Vot+½gt The rocket deploys a parachute after 9 seconds and descends at a constant rate of 20 ft/sec. How long does it take to reach the ground? Plot the...
show work 4. Suppose a stone is launched vertically upward with initial velocity 32 ft/sec from...
show work
4. Suppose a stone is launched vertically upward with initial velocity 32 ft/sec from a height of 48 ft above ground. After t seconds its height is given by s(t) = -16t2 + 32t + 48 At the time when the stone hits the ground it is moving with a speed of A. 32 ft/s B. 24 ft/s C. 64 ft/s D. 48 ft/s E. 96 ft/s
A ball is thrown vertically upward with an initial velocity of 96 feet per second
A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2a.) at what time will the ball strike the groundb.) for what time t is the ball more than 128 feet above the ground?c.) when will the ball reach its highest peak? how high is it above the ground?
A model rocket is launches upward with an initial velocity of 160 feet per second
A model rocket is launches upward with an initial velocity of 160 feet per second. The height, in feet, of the rocket t seconds after the launch is given by h=-16t^2+160t. How many seconds after the launch will the rocket be 290 feet above the ground? Round to the nearest tenth of a second.
Carlon launched a toy rocket vertically up from ground level (y = 0 m), at time...
Carlon launched a toy rocket vertically up from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration of 12.3 m/s2 during the burn phase. At the instant of engine burnout the rocket has risen to 89 m. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The maximum height reached by the rocket is closest to:
A rocket is launched straight up from the ground with constant acceleration. When it reaches a...
A rocket is launched straight up from the ground with constant acceleration. When it reaches a height of 240m, a bolt falls off the side of the rocket. The bolt hits the ground 6.0s later. A) How fast was the bolt (or rocket) going when it broke loose from the rocket? B) What was the rocket's acceleration? C) What was the maximum height that the bolt reached? Thanks.
A toy rocket is launched upward with an initial velocity of 64ft/s from a platform that is 80ft. above the ground. The acceleration of the rocket is a(t) = -32ft. Find the height of the rocket after t seconds. When does it hit the ground? Use calculus methods to solve the problem.
by matlab programm please
3. A rocket is launched straight into the air with initial velocity 200 ft/s. Assume the launch is instantaneous. How high will it go, and how long will that take (use time increments of 0.01 seconds)? G-- 32.2 ft/s, Ho-0 (the ground) V(t)-Vo+ g t H(t) Ho+ Vot+½gt The rocket deploys a parachute after 9 seconds and descends at a constant rate of 20 ft/sec. How long does it take to reach the ground? Plot the...
show work
4. Suppose a stone is launched vertically upward with initial velocity 32 ft/sec from a height of 48 ft above ground. After t seconds its height is given by s(t) = -16t2 + 32t + 48 At the time when the stone hits the ground it is moving with a speed of A. 32 ft/s B. 24 ft/s C. 64 ft/s D. 48 ft/s E. 96 ft/s
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