The distance d of point P to the line through points A and B is the length of the component of AP that is orthogonal to AB, as indicated in the diagram.
So the distance from P = (4,3) to the line through the points A = (-2,5) and B (-3, -5) is _______
This problem is based on finding out distance between point and the line that passes through two points
The distance d of point P to the line through points A and B is the length of the component of AP that is orthogonal to AB, as indicated in the diagram.
The distance d of a point P to the line through points A and B is the length of the component of AP that is orthogonal to AB, as indicated in the diagram. So the distance from P = (-3,2,3) to the line through the points A = (2, -4, 2) and B = (0,3,-1) is _______
(1 point) The distance d of a point P to the line through points A and B is the length of the component of AP that is orthogonal to AB, as indicated in the diagram. = So the distance from P (-4,-5, -4) to the line through the points A = (1, -2, 3) and B = (-3, 2, -3) is | (1 point) The distance d of a point P to the line through points A and B is...
(1 point) The distance d of a point P to the line through points A and B is the length of the component of AP that is orthogonal to AB, as indicated in the diagram. So the distance from P = (0, 2) to the line through the points A = (-1,-1) and B=(3,0) is
Problem-1 (10 points): The line L through the point p(-1,0,1) is orthogonal to the surface S-((r, y.3)r In:+sin(y:)- 0 at p. Then L intersects the plane :-0 at the point
Problem-1 (10 points): The line L through the point p(-1,0,1) is orthogonal to the surface S-((r, y.3)r In:+sin(y:)- 0 at p. Then L intersects the plane :-0 at the point
Question 1 (10 points] Let L be the line passing through the point P=(4, -2,5) with direction vector d=[5, 2, 2]', and let T be the plane defined by –2x-3y=z=-5. Find the point Q where L and T intersect. Q=(0,0,0)
B (2,4) A (-2,3) C (11,2) 0 3y+ 2x+5-0 In the diagram, the points A, Band C have coordinates (-2,3), (2,4) and (11,2) respectively. D is a point such that DA is perpendicular to AB, and Dlies on the line 3y+ 2x+ 5 = 0. 141 Find the coordinates of D. Point E lies on DC and the ratio of the length of DE to the length of DCis 2:3 (i) 141 (ii) Find the area of triangle DBE. (ii)...
Question B
Diagram NOT accurately drawn 2 2b APB is a triangle. N is a point on AP. AB- a AN 2b NP-b (a) Find the vector PB, in terms of a and b. 3b 10 B is the midpoint of AC. M is the midpoint of PB. *(b) Show that NMC is a straight line.
Diagram NOT accurately drawn 2 2b APB is a triangle. N is a point on AP. AB- a AN 2b NP-b (a) Find the...
5. Find parametric equations for the line through the point (0, 1,2) that is orthogonal to the line x = 1 + t, y 1-t, 2t, and intersects this line. (Hint: Try drawing this scenario in two dimensions, ie. draw two orthogonal lines and a point on each line away from the intersection. How would you find the direction vector?)
Determine the slope (g) and deflection (AB) of Point B in terms of El. P = 12 kN and L = 9 m. Use the Moment-Area Method. Theorem 1: The angle between the tangents at any two points on the elastic curve equals the area under the M EI diagram between these two points. ALI Theorem 2: The vertical distance between the tangent at a point (A) on the elastic curve and the tangent extended from another point (B) equals...
Two points, A and B, are terminal ends of a line-segment (place horizontally). Point X is above the line a distance 23- cm away from point A (nearer to A than B). Point Z is above the line a distance 12-cm away from point B (nearer to B than A). The point T is below the line. As such, there are line segments XT and ZT each of which crosses the line segment AB. The distance from point X to...