Question

Two aqueous sulfuric acid (H2SO4) solutions containing 20.0 wt% H2SO4 (SG=1.139) and 80.0 wt% H2SO4 (SG=1.727) respectively, are mixed to form a 4.00 molar solution (mol/L) (SG=1.213).

1. Calculate the mass fraction of sulfuric acid in the product stream. Atomic weight: H=1g/mol, O=16g/mol, S=32g/mol.
2. Taking 100 kg of the 20 wt% feed solution as a basis, calculate the volumetric feed ratio of 20.0 wt% H₂SO₄ to 80.0 wt% H₂SO₄, to 2 decimal places.

Answer 1

Ans. Two splections (SG=1139) 20 ot / H2SO4 (A) 80 cott H₂ SD 4 4 molar ma mely (542 1.213) (SG = 1727 (B) let basis of 100 kg of 20 wt 7 H2SDA. f moles Hasoy, in a t moles H2SD u io B - moles of resou enc Am solection - 4 miles d & Hesoy 1 litre solution 1:213 Ka solection et selecter Density of solution Kg Hence A mal / H2SO4 1.218 kg of solution (6) Total mass of of c mass of At mass of B

2 1.139 VA +1.498 VR mc moles balance of H2SO4 ts - NA tna - no (0.2) (1.139 VA) X 103 6.6) [1.498VB) x103 + 98 98 4 [1139 VA + 1.49880 1.213 solving this equation - VAB 2.95 4 ml of H2SO4 1.213 kg of solution mass of the spy in C = 4x98 gn 92 kg So mass fraction 0.892 kg 0 392 1213 kg 0.3231