Question

Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O. Suppose 33.3 g of sulfuric acid is mixed with 12. g of sodium hydroxide. Calculate the minimum mass of sulfuric acid that could be left over by the chemical reaction. Round your answer to 2 significant digits.

Answer 1

H2504 + 2 NaOH = 'Naz S04 + 2H2O 03.30 33.39 = 0,3395 mol 4:980999/mo Moles of NagH = 39.997 g/mol A NaoH = - 12:00 - 0,3000mol 2 mol of NaOH react with H2SO4= I mol 0,30 mol of NaOH react with Hz 364 = Beli Imol x 0.30 mo! 2 mol = 0,1500 mol - Moles of H2SO4 left = (0,3395-0.1500) mol = 0,1895 mol So, the minimum mass of H2 504 left!!!! = 0,1895 mol *98.079g/mol = 118,5868]