Question

O CHEMICAL REACTIONS Limiting reactants Aqueous sulfuric acid (H2SO4) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium sulfate (Na2SO4) and liquid water (HO). Suppose 96. g of sulfuric acid is mixed with 127. g of sodium hydroxide. Calculate the minimum mass of sulfuric acid that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits. 5 ?

Answer 1

q8g We have 96 g H₂ SO4 and 127g of Na on . Balanced equation is :- M, SO4 (29) +2 Na Oman) → Naz Soyley + 2 1294) Imole amole Imole amole 18989 2x 40g 1x 1429 28189 sog 1429 1 369 Imole of H₂SO4 react with 2 mole of Na On to produce I mole of Na2SO4 and 2 mole of H₂O. 98 g of H₂ SOu react with sog of NaOH to produce 142g of Na₂SO4 and 36g of H₂O. 98 g of H₂ Sou react with NaOH = dog Ig of H₂ Soy react with Na On = 80 g 96g of H₂SO, react with Na On = 80 x 96 g 1 =78.37 g 96g of H₂SO4 will react with 78.37 g of NaOH

But we have 127g of Na OH . So, H₂ SOy is in limited amound and Na on is in excess. H₂SO4 is limiting reagent and Na on is excess reagent. H₂SO4 left amount is Og Left amount of NaOH = 1279 - 78.37g 1. = 48.63g = 48.6g =49g Left amount of H₂SO4 = 0.0 g