Question

Aqueous sulfuric acid (H2SO4) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium sulfate (Na2SO4) and liquid water (H20). Suppose 19. g of sulfuric acid is mixed with 6.99 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits. x ?

Answer 1

Page no: Answer: Reaction & Hy sou (aq) + 2 NaOH (a) — Na 2 soulaq) + 2 H20(1). Now - mass of H₂ sou = 19.0 grams. Molar mass of Hosou: 98.079 g/mol moles of H, so mass Molax mass 190 98.079 0.193 mol Now mass of Nooh = 6.90. goams. Molar mass of NaOH = noog/mole. moles of waoh = mass Molar mass : 6.99 40.0" 0.1747 mol Now, from the reaction. I mole of Hq sou combines with 2 moles of Naoh so, 0.193 moles of Hq sou combines with. : 2x0-193 = 0.386 moles of waoh But we have only alla moles of Nach

1 page noir. reactant and Hason is the. .. Noch is the limiting excess reactant, Now, a moles of Nach produces Imole of Nassou so, moler of Naoh Pooduces 50's moles of Na, som of waoh produces Therefore, 0.386.moles -0.386 x 0.5 = 0.1931 moles of Na,son Molar mass of wa,son = 142.ou g/mol Mass. of na, sou produced - Moles x molar mass : 0.193.1 x 142.00 27.42