For each of the reactions, calculate the mass (in grams) of the duct that forms when 3.67 g of the underlined reactant completely reacts. Assume that there is more than enough of the other react
a) Ba + Cl2 --------> BaCl2
3.67g/137.3g/mol xs 0 initial moles
0 xs 3.67/137.3 moles after rxn
Thus mass of BaCl2 = moles x molar mass
= 3.67/137.3 molx 208.3g/mol
=5.57 g
b) CaO + CO2 ---------> CaCO3
3.67g/ 56g/mol xs 0 initial mol
0 xs 3.67g/ 56g/mol
mass of CaCO3 formed = 3.67g/ 56g/mol x100g/mol
= 6.55 g
c) 2Mg +O2 ---------> 2 MgO
3.67g/24g/mol xs 0 initial moles
0 - 3.67g/24g/mol after rxn
mass of MgO formed = 3.67g/24g/mol x40g/mol
=6.12 g
d)4Al +3O2 ---------------> 2Al2O3
3.67/27mol xs 0 initial moles
0 xs (1/2 )x3.67/27mol
mass of AL2O3 formed = (1/2 )x3.67/27mol x 102g/mol
= 6.93 g
For each of the reactions, calculate the mass (in grams) of the duct that forms when 3.67 g of the underlined reactant completely reacts
For each of the reactions, calculate the mass (in grams) of the product formed when 3.14 g of the underlined(bold) reactant completely reacts. Assume that there is more than enough of the other reactant. Ba(s)+Cl2(g)→BaCl2(s) CaO(s)+CO2(g)→CaCO3(s) 2Mg(s)+O2(g)→2MgO(s) 4Al(s)+3O2(g)→2Al2O3(s)
For each of the reactions, calculate the mass (in grams) of the product formed when 15.34 g of the bolded reactant completely reacts. Assume that there is more than enough of the other reactant. 1. 2K(s)+Cl2(g)−−−−−→2KCl(s) 2. 2K(s)+Br2(l)−−−−−→2KBr(s) 3. 4Cr(s)+3O2(g)−−−−−→2Cr2O3(s) 4. 2Sr(s)−−−−+O2(g)→2SrO(s)
For each of the reactions, calculate the mass (in grams) of the product formed when 15.46 g of the BOLD reactant completely reacts. Assume that there is more than enough of the other reactant. Express your answer using four significant figures. Part A 2K(s)+Cl2(g)––––––→2KCl(s) Answer: m= ? g Part B. 2K(s)+Br2(l)––––––→2KBr(s) Answer: m= ? g Part C 4Cr(s)+3O2(g)––––––→2Cr2O3(s) Answer: m= ? g Part D 2Sr(s)–––––+O2(g)→2SrO(s) Answer: m= ? g
Part A For the reaction Ca(s)+Cl2(g)--> CaCl2(s) calculate how many grams of the product form when 20.4 of Ca completely reacts. Assume that there is more than enough of the other reactant. Part B. For the reaction 2K(s)+Br2(l)-->2KBr(s) calculate how many grams of the product form when 20.4g of Br2 completely reacts. Assume theres more than enough. Part C. For the reaction 4Cr(s)+3O2(g)--->2Cr2O3(s) calculate how many grams of the product form when 20.4g of O2 completely reacts. Assume theres more...
31. For the reaction shown, calculate how many grams of oxy- gen form when each quantity of reactant completely reacts. 2 HgO(s) —> 2Hg(l) + O2(g) 0-521- (a) 2.13 g Hgo (b) 6.77 g Hgo (c) 1.55 kg Hgo (d) 3.87 mg Hgo 22. For each of the reactions, calculate how many grams of th 34. 33. For each of the reactions, calculate how many grams of the product form when 2.4 g of the reactant in color completely reacts....
For the reactation calculate how many grams of the product form when 3.0g of Na2O completely reacts assume that there is more than enough of the other reactant Na2O(s)+H2O>>>>2NaOH(aq)
For the reaction 4Cr(s)+3O2(g)→2Cr2O3(s) calculate how many grams of the product form when 15.4 g of O2 completely reacts. Assume that there is more than enough of the other reactant.
For the reaction 2K(s)+Br2(l)→2KBr(s) calculate how many grams of the product form when 20.4 g of Br2 completely reacts. Assume that there is more than enough of the other reactant.
34. For the reaction written below, calculate how many grams of the product form when 2.4 g of chlorine gas completely reacts. Assume there is more than enough of the other reactant. 2 Na (s) +Cl2 (g)-2 NaCI (s)
Part C For the reaction 4Cr(s) + 302(g) + 2Cr2O3(s) calculate how many grams of the product form when 20.4 g of O2 completely reacts. Assume that there is more than enough of the other reactant. I ALQ R O ?