Question

Part A For the reaction Ca(s)+Cl2(g)--> CaCl2(s) calculate how many grams of the product form when 20.4 of Ca completely reacts. Assume that there is more than enough of the other reactant.

Part B. For the reaction 2K(s)+Br2(l)-->2KBr(s) calculate how many grams of the product form when 20.4g of Br2 completely reacts. Assume theres more than enough.

Part C. For the reaction 4Cr(s)+3O2(g)--->2Cr2O3(s) calculate how many grams of the product form when 20.4g of O2 completely reacts. Assume theres more than enough.

Part D. For the reaction 2Sr(s)+O2(g) --->2SrO(s) Calculate how many grams of the product form when 20.4g of Sr completely reacts. Assume theres more than enough.

Answer 1

Part A

Ca (s) + Cl2 (g) ---------> CaCl2 (s)

40.08 g                               110.984 g

20.4 g                                     ??

mass of product formed = 20.4 x 110.984 / 40.08

                                       = 56.5 g

Part B.

2 K (s) +   Br2 (l)   ------------> 2 KBr(s)

                 159.81 g                     238 g

                  20.4 g                            ??

mass of product formed = 20.4 x 238 / 159.81

                                       = 30.4 g

Part C.

4Cr(s) + 3 O2 (g) ------------> 2 Cr2O3(s)

                96 g                             304 g

               20.4 g                            ??

mass of product formed = 20.4 x 304 / 96

                                      = 64.6 g

Part D.

2 Sr (s) + O2(g) ------------>   2 SrO(s)

175.24 g                                  207.2 g

20.4 g                                        ??

mass of product formed = 20.4 x 207.2 / 175.24

                                       = 24.1 g