Part A For the reaction Ca(s)+Cl2(g)--> CaCl2(s) calculate how many grams of the product form when 20.4 of Ca completely reacts. Assume that there is more than enough of the other reactant.
Part B. For the reaction 2K(s)+Br2(l)-->2KBr(s) calculate how many grams of the product form when 20.4g of Br2 completely reacts. Assume theres more than enough.
Part C. For the reaction 4Cr(s)+3O2(g)--->2Cr2O3(s) calculate how many grams of the product form when 20.4g of O2 completely reacts. Assume theres more than enough.
Part D. For the reaction 2Sr(s)+O2(g) --->2SrO(s)
Calculate how many grams of the product form when 20.4g of Sr
completely reacts. Assume theres more than enough.
Part A
Ca (s) + Cl2 (g) ---------> CaCl2 (s)
40.08 g 110.984 g
20.4 g ??
mass of product formed = 20.4 x 110.984 / 40.08
= 56.5 g
Part B.
2 K (s) + Br2 (l) ------------> 2 KBr(s)
159.81 g 238 g
20.4 g ??
mass of product formed = 20.4 x 238 / 159.81
= 30.4 g
Part C.
4Cr(s) + 3 O2 (g) ------------> 2 Cr2O3(s)
96 g 304 g
20.4 g ??
mass of product formed = 20.4 x 304 / 96
= 64.6 g
Part D.
2 Sr (s) + O2(g) ------------> 2 SrO(s)
175.24 g 207.2 g
20.4 g ??
mass of product formed = 20.4 x 207.2 / 175.24
= 24.1 g
Part A For the reaction Ca(s)+Cl2(g)--> CaCl2(s) calculate how many grams of the product form when...
For each of the reactions, calculate the mass (in grams) of the product formed when 15.34 g of the bolded reactant completely reacts. Assume that there is more than enough of the other reactant. 1. 2K(s)+Cl2(g)−−−−−→2KCl(s) 2. 2K(s)+Br2(l)−−−−−→2KBr(s) 3. 4Cr(s)+3O2(g)−−−−−→2Cr2O3(s) 4. 2Sr(s)−−−−+O2(g)→2SrO(s)
For the reaction 4Cr(s)+3O2(g)→2Cr2O3(s) calculate how many grams of the product form when 15.4 g of O2 completely reacts. Assume that there is more than enough of the other reactant.
For each of the reactions, calculate the mass (in grams) of the product formed when 15.46 g of the BOLD reactant completely reacts. Assume that there is more than enough of the other reactant. Express your answer using four significant figures. Part A 2K(s)+Cl2(g)––––––→2KCl(s) Answer: m= ? g Part B. 2K(s)+Br2(l)––––––→2KBr(s) Answer: m= ? g Part C 4Cr(s)+3O2(g)––––––→2Cr2O3(s) Answer: m= ? g Part D 2Sr(s)–––––+O2(g)→2SrO(s) Answer: m= ? g
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For the reaction 2K(s)+Br2(l)→2KBr(s) calculate how many grams of the product form when 20.4 g of Br2 completely reacts. Assume that there is more than enough of the other reactant.
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For the reactation calculate how many grams of the product form when 3.0g of Na2O completely reacts assume that there is more than enough of the other reactant Na2O(s)+H2O>>>>2NaOH(aq)
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