Question

Liquid hexane CH3CH24CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 51.7 g of hexane is mixed with 66. g of oxygen. Calculate the minimum mass of hexane that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer 1

produced compare coa from Hexane & oxygen 158.50 gm co produced from Hexane . 57.31m con produced from oxygen (limiting unit) calculate could be the minimum mass of left over by chemical Hexane Reaction Remaining -158.50 gm - Hexane * more of Hexane = mass mol, wt. 517 gan 86.11 grmol TEO.600 mole or нехат 66 am 32gfy. mol a mole of oxygen = massa moliest. 2,06 mole of the

produced compare coa from Hexane & oxygen 158.50 gm co produced from Hexane . 57.31m con produced from oxygen (limiting unit) calculate could be the minimum mass of left over by chemical Hexane Reaction Remaining -158.50 gm - Hexane * more of Hexane = mass mol, wt. 517 gan 86.11 grmol TEO.600 mole or нехат 66 am 32gfy. mol a mole of oxygen = massa moliest. 2,06 mole of the

stoichiometric Reaction a mole Hexane React with 19 mole 2006 mole 2 2 (limiting - Reactant) in needed Hexane = 2 * 2,06 19 y needed Hexame = 0,216 Bret Here given o.600 mole of Hexane but used only 0.216 mole so, Remaining onty (0.60o = 0,216) = 0.384 mode of Hexame 1 mass of Hexane = mole x mol.cat, of hexane = 0.384 x 86.11 gm.mot! mel 33, 96 9м оf Hexane Remaining