Balance the following chemical equation, then answer the following question.
C8H18(g) + O2(g) →CO2(g)+H2O(g)
How many grams of oxygen are required to react with 10.0 grams of octane (C8H18) in the combustion of octane in gasoline?
Balance the following chemical equation, then answer the following question. C8H18(g) + O2(g) →CO2(g)+H2O(g) How many...
14. For the following problem, use the following chemical equation: C8H18 (1) + O2(g) CO2(g) + H2O(g) a. Balance the chemical equation. b. How many moles of oxygen are needed to fully react 837.4 grams of C8H18?
Part A Determine the balanced chemical equation for this reaction. C8H18(g)+O2(g)?CO2(g)+H2O(g) Enter the coefficients for each compound in order, separated by commas. For example, 1,2,3,4 would indicate one mole of C8H18, two moles of O2, three moles of CO2, and four moles of H2O. 2,25,16,18 SubmitHintsMy AnswersGive UpReview Part Correct It is important to balance a chemical equation before using it for calculations. Checking that equations are balanced will help you avoid many errors in chemistry problems. Balanced chemical equation...
Combustion of Octane: C8H18 + O2 → CO2 + H2O Question 1: What are the coefficients for the balanced reaction of the combustion of octane? Problem 2: If 20 g of octane combust with 20 g of oxygen, which is the limiting reagent?
The combustion of octane (C8H18) in oxygen proceeds as follows 2 C8H18(g) + 25 O2(g) ---> 16 CO2 (g) + 18 H2O(l) How many moles of CO2are produced when 5.0 moles of octane, C8H18, is burned in 5.0 moles of oxygen?
Burning octane is: 2 (C8H18) + 25 (O2) ......... 16 (CO2) + 18 (H2O) How many moles of oxygen would you need to burn 2.37 moles of octane?
According to the following combustion reaction of gasoline (Octane), how many moles of C8H18 needs to be reacted to produce 16 moles of CO2? C8H18 (l) + 25/2 O2 (g) → 8CO2 (g) + 9 H2O
the complete combustion of octane , C8H18, a component og gasoline, proceed as 2 C8H18 +25 O2 = 16 CO2 + 18H2O. a) how many moles of CO2 are produced when 1.50 mol octance reacted? b) how many grams of water produced in this reaction? c)how many moles of oxygen required to form 90.0 g water?
Using the balanced equation for the combustion of ethanol, answer the following question. C2H6O(l) + 3 O2(g) → 2 CO2(g) + 3 H2O (g) How many grams of O2 are needed to react with 0.28 mol of ethanol?
Octane (C8H18) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). When the equation in balanced, the coefficient of octane is: C8H18+ O2 --> CO2 + H2O a.8 b. 16 c.25 d. 2
Use this balanced equation to answer the following stoichiometry problem. 2C3H18(1) + 25 O2(g) →16 CO2(g) + 18 H2O(g) The molar masses in grams are: C8H18 = 114; O2 = 32; CO, = 44; H20 = 18. If you burn 72.9 g of octane, how many liters at STP of CO2 are produced? O 179 L 129 L 83.5L 115L