Determine the osmotic pressure at 25 °C of an aqueous solution that is 0.028 M NaNO3....

Question

Question

Determine the osmotic pressure at 25 °C of an aqueous solution that is 0.028 M NaNO₃.

p = i M R T (R = 0.08206 atm L/mol K)

For some reason the answer is 1.37 atm, but I am getting .685 atm.

Answer 1

Answer #1

NANO3 = 2 ions, Na+ and NP3-

then

P = i*M*RT

P = 2*0.028*0.08206*(25+273) = 1.36941728 atm

You are CORRECT

we must account for NaNO3 dissociation Na+ and NO3-

which is i = 2

the answer you are providing (0.685 atm) does not accounts for that

Answer 2

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