A solution is prepared by dissolving 20.2 mL of methanol (CH3OH) in 100.0 mL of water...

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A solution is prepared by dissolving 20.2 mL of methanol (CH3OH) in 100.0 mL of water...

A solution is prepared by dissolving 20.2 mL of methanol (CH3OH) in 100.0 mL of water at 25 ∘C. The final volume of the solution is 118 mL. The densities of methanol and water at this temperature are 0.782 g/mL and 1.00 g/mL, respectively. For this solution, calculate mole percent

M=4.18

m=4.93

percent by mass= 13.6%

mole fraction= 8.15*10^-2

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Answer 1

Answer #1

The mole percent is the mole fraction x 100% so:

mole percent= 8.15x10^-2 x 100= 8.15%

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Answer 2

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