The combustion of propane gas (C3H8) is used to fuel barbeque grills. In order to produce 5.65 moles of water how many moles of oxygen gas are needed?
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l
As from balanced reaction
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)
4 moles of H2O require 5 moles of O2
So 5.65 miles of H2O require =5/4*5.65
=7.062 mole of O2 required
The combustion of propane gas (C3H8) is used to fuel barbeque grills. In order to produce...
12. Propane (C3H8) is used as a fuel in many gas grills. The balanced equation for the combustion of C3Hg is shown in Equation 10. C3H8(g) +502(g) + 3 CO2(g) + 4H2O(g) + energy (Eq. 10) (a) How many grams of CO2 could possibly be produced if 10.0 g of CzHg reacts with an ample supply of Oz? (b) How many grams of CO2 could possibly be produced with an ample supply of C3Hg, but only 10.0 g of O2?...
Propane, a component in natural gas, can be used as a fuel in combustion reactions. What is the maximum amount of work (in kJ) that could be supplied by the following reaction under the given conditions at 319 K? C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) where ΔHorxn = -2045 kJ, ΔSorxn = 103 J/K, and [C3H8] = 1.13 M, [O2] = 11.15 M, [CO2] = 7.35 M, and [H2O] = 1.49 M.
The combustion of propane (C3H8) produces CO2 and H2O: C3H3 (8) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) mol The reaction of 2.5 mol of O2 with 4.6 mol of C3H8 will produce _______ of H2O. A) 4.0 B) 3.0 C) 2.5 D)2.0 E) 1.0
The combustion of propane (C3H8) produces CO2 and H2O according to the following balanced equation: C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) If the hydrocarbon is present in excess, what mass of oxygen (O2) in grams is necessary to form 12.9 g of CO2? Round your answer to the nearest 0.1.
8.24 kg of propane gas is being used as fuel. Based on the reaction C3H8 + O2 ? CO2 + H2O, how many kilograms of carbon dioxide have been produced? (Note: Please make sure to balance the equation) 2.75 kg 8.24 kg 24.72 kg 31.26 kg
The propane, C3H8, in a fuel cylinder, undergoes combustion with oxygen in the air. C3H8(g)+5O2(g)⟶Δ3CO2(g)+4H2O(g) How many liters of CO2 are produced at STP if the cylinder contains 889 g of propane?
The thermochemical equation for the combustion of propane is: C3H8 (g) + 5 O2 (g) 3 CO2 (g) + 4 H2O (l) H = -2220 kJ What is the enthalpy change when 35.0 g of propane react?
calculate the enthalpy of the combustion of propane for your barbeque C3H8 + 5O2 -> 3CO2 + 4H2O propane -105 kJ/mol CO2 -394 kJ/mol Water -286 kJ/mol Ooxygen. 0
7. Propane is burned in air according to the chemical equation: C3H8(g) + 5 O2(g) ® 3 CO2(g) + 4 H2O(g) If you burn 455g of propane in air, a. How many moles of oxygen is required? ____________________ b. How many moles of CO2 would be produced? ____________________ c. How many moles of H2O would be produced?____________________ d. Why aren't the moles of CO2 and H2O not the same?
The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) The reaction of 7.5 mol of O2 with 1.4 mol of C3H8 will produce ________ mol of CO2. Group of answer choices.