a) Molar concentration = moles/volume = 1.727*10^-2 mole/0.025L = .69M
b)Only a portion of the HCl was neutralized by the antacid so we need to find how much HCl was neutralized by NaOH and then subtract that from thetotal HCl. ,so there is a 1-1 ratio of HCl to NaOH. Now to find the moles of NaOH: . This means thereare of HCLneutralized by NaOH which means there were .025-.0068= 0.0182L neutralized by antacid.
c)I'm not entirely sure what is meant by the this last question, but I am assuming that it is asking for the final volume of the antacid + theneutralized HCL which would be: 3ml+18.2ml = 21.2ml
4. A student analyzed an antacid tablet from a bottle of 48 tablets purchased at a discount store for $1.00. The mass of the tablet was 1.462g. After adding 25.00mL of 0.8000/M HCl solution to the tablet, the student back-titrated the excess HCI with 3.52 mL of 1.019M NaOH solution. (a) Calculate the number of moles of HCI added to the tablet (b) Calculate the number of moles of NaOH required for the back-titration (c) Calculate the number of moles...
Suppose a student adds 25.00 mL of 0.989 M HCl to a 1.54 g antacid tablet. The student uses 21.1 mL of 0.543 M NaOH to titrate the solution. Calculate the moles of acid neutralized per grams of tablet. __________mol/g
25.0 mL used of HCl Brand of Antacid: Meijer Cost of Antacid: 3.29 per 160 tablets Concentration of HCl solution, M: 0 939 A Concentration of NaOH solution, M: 0.927M Trial 1 Trial 3 1.147 g Trial 2 1.130 g 27.14 ml 1.1499 40.52 mL 13.40 mL 0.00 mL 13.40 mL 27.14 mL Mass of tablet, g Final buret reading mL Initial buret reading, mL Volume of Titrant, mL Number of moles of HCI added, mol Number of moles of...
A Tums tablet weighed 1.319 g. Using the procedure of this experiment, the tablet was dissolved in, and reacted with, an excess amount of HCl (125.00 mL of 0.101 M HCl). The excess unreacted HCl was titrated with NaOH; 18.75 mL of 0.101 M NaOH was used to reach the endpoint. Calculate the moles of HCl that did not react with the antacid. Calculate the moles of HCl that did react with the antacid. Calculate the mass of HCl that...
need to calculate tritation values correction trial 2 final volume of NaOH is 30.2ml EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Rugbu Cost of antacid 4.5 ¢ per tablet Average mass of tablet_1-30129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) .1006 Data Trial 1 Trial 2 Mass of sample (g) 0-104 Initial volume of HCl (mL 10.116 49.1 12101 4601 24.1 Final volume of HCl (mL) Initial volume of NaOH (mL 49.6 48.2 Final volume...
Lab Report: Evaluating the Cost-Effectiveness of Antacids Experimental Data Mass of Antacid 1. Antacid name Rolaids 123.653g 124.012g l0.359g 23.887g tms 2. Mass of empty flask 3. Mass of flask + antacid 3 मकस 1247g 4. Mass of antacid 0 310g Addition of HCI OTHHCI 0.09963 N0.09963 M 0.1l mL 5. Molarity of HCI 6. Initial buret reading 0.01mL 7. Final buret reading 40.09mL 40.08ML 3,993 meleS 40.00mL 34.89 mL 3.974 moles 8. Volume of HCI added 9....
need calculation for this tritation values please EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid Rugby 4, 5 per tablet Average mass of tablet 130129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) 01006 Data Trial 1 Trial 2 Mass of sample (g) 0.116 Initial volume of HCl (mL 0.9 0-104 3.9 22-2 Final volume of HCI (mL) Initial volume of NaOH (mL 28 0.4 34.2 7-8 Final volume of NaOH (mL) 30:2 140...
need calculation for this experiment EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid — Rugby 4. 5 € per tablet Average mass of tablet_1-30129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) 2.1006 Data Trial 1 Trial 2 Mass of sample (g) 0.116 49.1 Initial volume of HCI (mL 0-104 46.1 24-1 Final volume of HCI (mL) 21.) Initial volume of NaOH (mL 49.6 49.1 Final volume of NaOH (mL) 34.2 344 31-1 140...
Question 5 (10 points) If a student determined that 0.02351 moles of HCl was initial added to the beaker and 0.008952 moles of NaOH was calculated for the back titration. How many moles of HCl were neutralized by the antacid tablet (Note: the molar ratio of the reaction is 1:1 ; so there are 1 mole of HCI-to-1 mole of NaOH)? 0.014558 0.0014560 -0.014558 -0.01456 0.01456 RA
help on number 3 here is lab we did EXPERIMENT 19 An Analysis of Commercial Antacids Rolaids Alka Seltzer OBJECTIVES: Determine the per gram neutralizing ability of a commercial antacio Determine the per gram neutralizing ability of sodium bicarbonate Compare the effectiveness of several antacids. INTRODUCTION: "How do you spell relief two hecimie The parietal cells in the stomach secrete sufficient hydrochloric aci 0.10 M The flow of HCl increases when food enters the stomach and so acid secrete sufficient...