Suppose a student adds 25.00 mL of 0.989 M HCl to a 1.54 g antacid tablet....
Suppose a student adds 25.00 mL of 0.989 M HCl to a 1.54 g antacid tablet. The student uses 21.1 mL of 0.543 M NaOH to titrate the solution. Calculate the moles of acid neutralized per grams of tablet.
__________mol/g
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Suppose a student adds 25.00 mL of 0.989 M HCl to a 1.54 g
antacid tablet....
(1) A student is given an antacid tablet that weighs 5.4320 g. The tablet is crushed...
(1) A student is given an antacid tablet that weighs 5.4320 g. The tablet is crushed and 4.1220 g of the antacid is added to 200. mL of simulated stomach acid. It is allowed to react and then filtered. It is found that 25.00 mL of this partially neutralized stomach acid required 14.4 mL of a NaOH solution to titrate it to a methyl red end point. It takes 27.8 mL of this NaOH solution to neutralize 25.00 mL of...
2. A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed...
2. A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed and 4.3628 g of the antacid was added to 200 mL of simulated stomach acid. This was allowed to react and then filtered. It was found that 25.00 mL of this partially neutralized stomach acid required 8.50 mL of a NaOH solution to titrate it to a methyl red endpoint. It took 21.54 mL of this NaOH solution to neutralize 25.00 mL of the...
A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed and...
A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed and 4.3628 g of he antacid was added to 200 mL fo simulated stomah acid. This was allowed to react and the filtered. It was found that 25 mL fo this partially neutralized stomach acid required 8.5 mL of a NaOH solution to titrate it to a methyl red endpoint. If it took 25.5 mL of this NaOH solution to neutralize 25 mL of the...
25.0 mL used of HCl Brand of Antacid: Meijer Cost of Antacid: 3.29 per 160 tablets...
25.0 mL used
of HCl
Brand of Antacid: Meijer Cost of Antacid: 3.29 per 160 tablets Concentration of HCl solution, M: 0 939 A Concentration of NaOH solution, M: 0.927M Trial 1 Trial 3 1.147 g Trial 2 1.130 g 27.14 ml 1.1499 40.52 mL 13.40 mL 0.00 mL 13.40 mL 27.14 mL Mass of tablet, g Final buret reading mL Initial buret reading, mL Volume of Titrant, mL Number of moles of HCI added, mol Number of moles of...
4. A student analyzed an antacid tablet from a bottle of 48 tablets purchased at a...
4. A student analyzed an antacid tablet from a bottle of 48 tablets purchased at a discount store for $1.00. The mass of the tablet was 1.462g. After adding 25.00mL of 0.8000/M HCl solution to the tablet, the student back-titrated the excess HCI with 3.52 mL of 1.019M NaOH solution. (a) Calculate the number of moles of HCI added to the tablet (b) Calculate the number of moles of NaOH required for the back-titration (c) Calculate the number of moles...
need calculation for this experiment EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid —...
need calculation for this experiment
EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid — Rugby 4. 5 € per tablet Average mass of tablet_1-30129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) 2.1006 Data Trial 1 Trial 2 Mass of sample (g) 0.116 49.1 Initial volume of HCI (mL 0-104 46.1 24-1 Final volume of HCI (mL) 21.) Initial volume of NaOH (mL 49.6 49.1 Final volume of NaOH (mL) 34.2 344 31-1 140...
A portion of a crushed antacid tablet is analyzed by a back-titration. First 50.00 mL of...
A portion of a crushed antacid tablet is analyzed by a back-titration. First 50.00 mL of 0.1250 M HCl is added to the tablet; then 12.51 mL of 0.1234 M NaOH is added to titrate the excess acid and reach the endpoint. Calculate the number of moles of HCl that reacted with the antacid.
need calculation for this tritation values please EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of...
need calculation for this tritation values please
EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid Rugby 4, 5 per tablet Average mass of tablet 130129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) 01006 Data Trial 1 Trial 2 Mass of sample (g) 0.116 Initial volume of HCl (mL 0.9 0-104 3.9 22-2 Final volume of HCI (mL) Initial volume of NaOH (mL 28 0.4 34.2 7-8 Final volume of NaOH (mL) 30:2 140...
1. A particular brand of antacid contains 500 mg of CaCO3 per 2.0 g tablet according...
1. A particular brand of antacid contains 500 mg of CaCO3 per 2.0 g tablet according to the label. How many mol of CaCO3 are contained in one tablet? nCaCO3 = ___ mol Ans. 0.005mol 2. The reaction by which the antacid neutralizes HCl is 2 HCl(aq) + CaCO3(s) à CaCl2(aq) + CO2(g) + H2O(l) How many moles of HCl can be neutralized by one tablet? nHCl = 0.010 mol 3. 50.0 mL of 0.300 M HCl are used to...
A student dissolves 0.326 g of a powdered antacid in 32.36 mL of 0.1034 M HCl....
A student dissolves 0.326 g of a powdered antacid in 32.36 mL of 0.1034 M HCl. The student boils the mixture and then allows it to cool. Lastly, the student adds phenolphthalein indicator to the mixture. 4) How many moles of HCl reacted with the antacid? How many equivalents of antacid are present in the sample?
2. A student is given an antacid tablet that weighed 5.6832 g. The tablet was crushed and 4.3628 g of the antacid was added to 200 mL of simulated stomach acid. This was allowed to react and then filtered. It was found that 25.00 mL of this partially neutralized stomach acid required 8.50 mL of a NaOH solution to titrate it to a methyl red endpoint. It took 21.54 mL of this NaOH solution to neutralize 25.00 mL of the...
25.0 mL used
of HCl
Brand of Antacid: Meijer Cost of Antacid: 3.29 per 160 tablets Concentration of HCl solution, M: 0 939 A Concentration of NaOH solution, M: 0.927M Trial 1 Trial 3 1.147 g Trial 2 1.130 g 27.14 ml 1.1499 40.52 mL 13.40 mL 0.00 mL 13.40 mL 27.14 mL Mass of tablet, g Final buret reading mL Initial buret reading, mL Volume of Titrant, mL Number of moles of HCI added, mol Number of moles of...
4. A student analyzed an antacid tablet from a bottle of 48 tablets purchased at a discount store for $1.00. The mass of the tablet was 1.462g. After adding 25.00mL of 0.8000/M HCl solution to the tablet, the student back-titrated the excess HCI with 3.52 mL of 1.019M NaOH solution. (a) Calculate the number of moles of HCI added to the tablet (b) Calculate the number of moles of NaOH required for the back-titration (c) Calculate the number of moles...
need calculation for this experiment
EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid — Rugby 4. 5 € per tablet Average mass of tablet_1-30129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) 2.1006 Data Trial 1 Trial 2 Mass of sample (g) 0.116 49.1 Initial volume of HCI (mL 0-104 46.1 24-1 Final volume of HCI (mL) 21.) Initial volume of NaOH (mL 49.6 49.1 Final volume of NaOH (mL) 34.2 344 31-1 140...
need calculation for this tritation values please
EXPERIMENT 11 LABORATORY REPORT Brand of Antacid Cost of antacid Rugby 4, 5 per tablet Average mass of tablet 130129_per tablet Concentration of HCl solution (M) 0.0979 Concentration of NaOH solution (M) 01006 Data Trial 1 Trial 2 Mass of sample (g) 0.116 Initial volume of HCl (mL 0.9 0-104 3.9 22-2 Final volume of HCI (mL) Initial volume of NaOH (mL 28 0.4 34.2 7-8 Final volume of NaOH (mL) 30:2 140...
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