A student dissolves 0.326 g of a powdered antacid in 32.36 mL of 0.1034 M HCl....
A student dissolves 0.326 g of a powdered antacid in 32.36 mL of 0.1034 M HCl. The student boils the mixture and then allows it to cool. Lastly, the student adds phenolphthalein indicator to the mixture.
4) How many moles of HCl reacted with the antacid? How many equivalents of antacid are present in the sample?
Homework Answers
Ans :
Number of moles of HCl = moalrity x volume (L)
= 0.1034 x 0.03236
= 0.003346 mol
Since equimoalr amount of antacid is neutralised by the HCl in the reaction and HCl has one equivalent per mole , so the number of equivalents of antacid in the sample will be 0.003346.
Add Answer to:
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please help me answer 1-3. My avergae number of mL of 0.100M
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