Given the following thermodynamic data, calculate the lattice energy of CaBr2(s).
Term Value (kJ/mol)
ΔH∘f[CaBr2(s)] -675
ΔH∘f[Ca(g)] 178
ΔH∘f[Br(g)] 112
I1(Ca) 590.
I2(Ca) 1145
EA(Br) -325
Express your answer to four significant figures, and include the appropriate units.
Given the following thermodynamic data, calculate the lattice energy of CaBr2(s). Term Value (kJ/...
Question 10 1 pts Given the following thermodynamic data, calculate the lattice energy of CaBrz(s). Term Value (kJ/mol) AH°formation[CaBr2(s)] -675 AH sublimation Ca(g)] 178 AH Sublimation[Brz(s)] 31 AH°bond energy[Br2(g)] 194 IE(Ca) IE2(Ca) Ea(Br) 590. 1145 -325 Enter your answer in units of kJ.
< 4 of Review I Constants I Periodic Given the following thermodynamic data, calculate the lattice energy of CaBr2 (s). Value (kJ/mol) Term AHCaBr2(s) -675 AH(Ca(g)) 179 AHvap Br2(1) AHbond Br2(g) 30.8 193 I(Ca) 590. I2(Ca) 1145 E(Br) -325 Note that the overall formation of gaseous bromine atoms from liquid bromine molecules can be thought of as consisting of two steps, vaporization of the liquid to the gas followed by dissociation of the gaseous molecules into the component gaseous atoms....
Calculate the lattice energy of knowing that:The standard heat of formation of is -675 .The first ionization energy of is 590 anditssecond ionization energy is 1145 .The heat of sublimation of is 178 .The bond energy of is 193,the heat of vaporization of is 31 ,and the electron affinity of is -325 .Thank you!
A. Calculate the lattice energy of NaI(s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea. Na(s) ΔHsublimation = 88 kJ/mol Na(g) Ionization energy = 476 kJ/mol I-I(g) Bond energy = 131 kJ/mol I(g) Electron affinity = -315 kJ/mol NaI(s) ΔH°f = -308 kJ/mol kJ/mol Do you expect this value to be larger or smaller than the lattice energy of...
Calculate the lattice energy of CaCl2 given the following thermodynamic data: Reactions Energies (kJ/mol) Ca (s) --> Ca (g) 178.0 Ca (g) --> Ca+ (g) + e- 590.0 Ca+ (g) --> Ca2+ (g) + e- 1145 Cl2 (g) --> 2 Cl (g) 242.6 Cl (g) + e- --> Cl- (g) -348.7 Ca (s) + Cl2 --> CaCl (s) ΔHof = -795.0
Calculate the lattice energy of AgF(s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea. Ag(s) Asublimation -265 kJ/mol Ag(g) Ionization energy-711 kJ/mol F-F(g) Bond energy- 138 kJ/mol F(g) Electron affinity348 kJ/mol AgF(s) AHor-225 kJ/mol kJ/mol Do you expect this value to be larger or smaller than the lattice energy of AgCI(s)?
Part A Use the Born-Haber cycle, data from Appendix llBand the following table to calculate the lattice energy of Cao. (AsubH for calcium is 178 kJ/mol: EA 141 kJ/mol, EA 744 kJ/mol: IEC 590 kJ/mol. IE2 1145 kJ/mol. TABLE 9.1 Average Bond Energies Bond Energy Bond Energy Bond Energy Bond kJ mo 1) Bond (kJ mol 1) Bond (kJ mol 237 414 418 218 389 946 193 464 208 H 0 N-0 222 590 565 272 51 200 H-Br 364...
Calculate the lattice energy of LiBr(s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea. Li(s) AHgublimation 139 kJ/mol Li(g Ionization energy-500 kJ/mol Br-Brig Bond energy 173 kJ/mol Br(g) Electron affinity 345 kJ/mol LiBr(s) AH°f-371 kJ/mol kJ/mol Submit Answer Retry Entire Group 8 more group attempts remaining Calculate the lattice energy of LiBr(s) using the following thermodynamic data (all data...
Calculate the lattice energy of RbH(s) using the following thermodynamic data (all data is in kJ/mol). Rb(s) AHŞublimation = 61 kJ/mol Rb(g) Ionization energy = 383 kJ/mol H-H(g) Bond energy = 416 kJ/mol Hg) Electron affinity = -93 kJ/mol RbH) AHºr= -72 kJ/mol kJ/mol
Construct a Born-Haber cycle and calculate the lattice energy of CaC2 (s). Note that this solid contains the diatomic ion C22–.Useful Information:?H°f (CaC2(s)) ?Hsub (Ca (s)) ?Hsub (C (s)) Bond dissociation energy of C2 (g) = +614 kJ/molFirst ionization energy of Ca (g) = +590 kJ/mol Second ionization energy of Ca (g) = +1143 kJ/mol First electron affinity of C2 (g) = –315 kJ/mol Second electronaffinity of C2 (g) = +410 kJ/mol= –60 kJ/mol = +178 kJ/mol = +717 kJ/mol