A 52.0 mL volume of 0.35 M CH3COOH (Ka= 1.8x10^-5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 33.0 mL of NaOH. Express answer numerically. (pH=?)
moles acetic acid = 0.0520 L x 0.35 M=0.0182
moles NaOH = 0.0330 L x 0.40 M=0.0132
CH3COOH + OH- = CH3COO-
moles acetic acid = 0.0182 - 0.0132 =0.0050
moles acetate = 0.0132
pKa = 4.74
pH = 4.74 + log 0.0132/ 0.0050=5.16
A 52.0 mL volume of 0.35 M CH3COOH (Ka= 1.8x10^-5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of...
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