Question

In the reaction, CaCO3(s)⟶CaO(s)+CO2(g)

how many liters of carbon dioxide, CO2, measured at STP, would be produced from the decomposition of 309 g of calcium carbonate, CaCO3?

Answer 1

Caco,(s) - Cao (s) + CO₂(g) I mole 100.0869 glmol I mole of Cacoas) will give 1 mol of co2 I mole of Calols) will give 22.4 litre ie, 100.0869 g of calges will give 22.4 L of CO₂ 1 g of cauges) will give 22.4 L of co 1000 8699 309 g of cacos will give 22.42 x 309 g of ca 100.08tag = 69.16 L of co, Note: I mole of any gas at STP occupies 22.4 litres of volume