Question

Ammonium phosphate ((NH4)3PO4) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H3PO4) with ammonia (NH3). What mass of ammonium phosphate is produced by the reaction of 4.81 g of ammonia?

Answer 1

Here is the Solution:

. We need to find out the mass (in grams) of ammonium phosphate, (NH4)3PO4 is produced by the reaction of 4.81 g of ammonia. o Given, 4.81 gram of ammonia. .We know that the molar mass of Ammonia NHz is: 17.031 g/mol . And the molar mass of Ammonium phosphate, (NH4)2PO4 is: 149.09 g/mol • The balanced chemical equation is: H3PO4 +3NH3 (NH4)3PO4 The balanced chemical equation says that, the mole ratio of NH3 and (NH4)2PO4 is 3:1 So, the mass of ammonium phosphate will be produces - 1 mol NH3 1 mol (NH )3PO4 149.09g (NH4)3PO4 *193*17.031 g NH* 3 mol NHA ^ 1 mol (NH2)-PO, 1 moltz 1 mol (NH43PO4 149.09 g (NH4)3PO4 = 4.81 g NH3 X 1703LNKX * 17.031 g NIKE* 3 mol MHz 1 mol (NH4)3PO4 = 14.0356 g (NH4)3PO4 -X OR = 14.04 g (NH4)2PO4

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