2-Ethoxy-2,3-dimethylbutane reacts with concentrated aqueous HI to form two initial organic products (A and B). Further reaction with HI produces organic product C from product B. Draw the structures of these three products.
2-Ethoxy-2,3-dimethylbutane reacts with concentrated aqueous HI to form two initial organic products (A and B). Further...
2-Ethoxy-2,3-dimethylbutane reacts with concentrated aqueous HI to form two initial organic products (A and B). Further reaction with HI produces organic product C from product B. Draw the structures of these three products.
Diisopropyl ether reacts with concentrated aqueous HI to form two initial organic products (A and B). Further reaction with HI produces organic product C from product B. Draw the structures of these three products.
Diisopropyl ether reacts with concentrated aqueous HI to form two initial organic products (A and B). Further reaction with HI produces organic product C from product B. Draw the structures of these three products.
Benzyl ethyl ether reacts with concentrated aqueous HI to form two initial organic products (A and B). Further reaction of product B with HI produces organic product C. Draw the structures of these three products.
Benzyl ethyl ether reacts with concentrated aqueous HI to form two initial organic products (A and B). Further reaction of product B with HI produces organic product C. Draw the structures of these three products.
Ethers react with HI to form two cleavage products. One of the products might react further with HI. In the first box below draw the two major products that could be recovered after treatment with one equivalent of HI. In the second box draw the two major products that could be recovered after treatment with excess HI. (If a product of the first step does not undergo additional reaction with excess HI, repeat its structure in the second box.) Ethers...
When 2-bromo-3-methylbutane reacts with ethanol,two products are formed, 2-ethoxy-3-methylbutane and 2-ethoxy-2-methylbutane. 1.Give an explanation for the two products. 2. Draw the full mechanism for the formation of the second product. (mechanism should have fours steps in total, including a deprotonation step.) Please show all work!
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The reaction of 2,3-dibromobutane with two equivalents of strong base gives three different products, each of which contains two new T-bonds. Product A has two sp-hybridized carbons, product B has one sp-hybridized carbon, and product C has none. Draw the structures of products A, B, and C. (0.6 pts)
Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonation of alcohol and oxygen to form anoxonium ion.Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products ofthis reaction.The 3.) is correct that is the minor product I came up with but I cant get the answer correct for 1.) major product? and 2.) minor product