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When 2-bromo-3-methylbutane reacts with ethanol,two products are formed, 2-ethoxy-3-methylbutane and 2-ethoxy-2-methylbutane. 1.Give an explanation for the...

When 2-bromo-3-methylbutane reacts with ethanol,two products are formed, 2-ethoxy-3-methylbutane and 2-ethoxy-2-methylbutane.

1.Give an explanation for the two products.

2. Draw the full mechanism for the formation of the second product. (mechanism should have fours steps in total, including a deprotonation step.)

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Answer #1

1) The reaction of ethanol with 2-bromo-3-methylbutane proceeds via SN1 mechanism which involves the formation of a carbocation intermediate. In this case one product is formed from the carbocation arising directly out of C-Br bond dissociation.

However, the original carbocation can also rearrange via 1,2- hydride shift to give a more stable carbocation. This rearranged more stable carbocation gives rise to the second product.

2)

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