At 900 K the following reaction has
Kp=0.345:
2SO2(g)+O2(g)???2SO3(g)
In an equilibrium mixture the partial pressures of SO2 and O2 are
0.150atm and 0.465atm , respectively.
What is the equilibrium partial pressure of SO3 in the mixture?
At 900 K the following reaction has Kp=0.345: 2SO2(g)+O2(g)???2SO3(g) In an equilibrium mixture the partial pressures...
Assignment 22 Chap 15: Applications of Equilibrium Constants At 900 K the following reaction has Kp=0.345: 2SO2(g)+O2(g)⇌2SO3(g) In an equilibrium mixture, the partial pressures of SO2 and O2 are 0.120 atm and 0.440 atm , respectively. What is the equilibrium partial pressure of SO3 in the mixture?
The equilibrium constant in terms of pressures, Kp, for the reaction of SO2 and O2 to form SO3 is 0.365 at 1.15×103 K: SO2(g) + O2(g) = 2SO3(g) A sample of SO3 is introduced into an evacuated container at 298 K and allowed to dissociate until its partial pressure reaches an equilibrium value of 0.867 atm. Calculate the equilibrium partial pressures of SO2 and O2 in the container. PSO2 = PO2 =
QUESTION 10 [CLO-6] At 900 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2502 + O2(g) ==== 2503 (g) At equilibrium, the partial pressure of SO2 is 35.0 atm and that of O2 is 15.9 atm. The partial pressure of SO3 is atm 4.21 x 10-3 6.20 x 10-4 82.0 40.2 192
A reaction vessel contains an equilibrium mixture of SO2, O2,, and SO3. The reaction proceeds such that: 2SO2 (g) + O2 (g) ----> <---- 2SO3 (g) The partial pressures at equilibrium are Pso2=0.001111 atm PO2 = 0.002728 atm PSO3 =0.0166 Calculate the Kp for the reaction.
The equilibrium constant, Kp, for the following reaction is 2.74 at 1150 K. 2SO3(g) 2SO2(g) + O2(g) If ΔH° for this reaction is 198 kJ, what is the value of Kp at 1260 K? Kp= ?
The equilibrium constant, Kp, for the following reaction is 2.74 at 1150 K. 2SO3(g) 2SO2(g) + O2(g) If ΔH° for this reaction is 198 kJ, what is the value of Kp at 1270 K? Kp =
At a given temperature, the equilibrium constant Kc for the reaction 2SO2(g)+O2(g)<==>2SO3(g) is 2.99x10^-3. What is the value of the equilibrium constant for each of the following reactions at that temperature? a. SO2(g)+ 1/2 O2(g)<==> SO3(g) b. 2SO3(g)<==>2SO2(g)+O2(g) c. SO3(g)<==> SO2(g)+ 1/2 O2(g)
The equilibrium constant for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) is 7 × 103 at a certain temperature. If at equilibrium, [SO2] = 0.0451 M and [O2] = 0.078 M, what is the equilibrium [SO3]?
Consider the following reaction where Kc = 34.5 at 1150 K: 2SO2(g) + O2(g) =2SO3(g) A reaction mixture was found to contain 4.39x10-2 moles of SO2(g), 4.28x10-2 moles of O2(g) and 4.23x10-2 moles of SO3(), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium SO3(g) must be consumed. 2. In order to reach equilibrium Kc must decrease. 3. In order to reach equilibrium SO2 must be consumed....
Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2SO2(g)+O2(g)→2SO3(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur dioxide, oxygen, and sulfur trioxide has the following composition: Calculate the value of the equilibrium constant Kp for this reaction. Round your answer to 2 significant digits. compound pressure at equilibrium SO2 58.3 atm 02 84.7 atm SO3 66.3 atm