The equilibrium constant in terms of pressures, Kp, for the
reaction of SO2 and O2 to form
SO3 is 0.365 at 1.15×103
K:
SO2(g) + O2(g) = 2SO3(g)
A sample of SO3 is introduced into an evacuated
container at 298 K and allowed to dissociate until
its partial pressure reaches an equilibrium value of
0.867 atm. Calculate the equilibrium partial
pressures of SO2 and O2 in the
container.
PSO2 =
PO2 =
The equilibrium constant in terms of pressures, Kp, for the reaction of SO2 and O2 to...
The equilibrium constant in terms of pressures, Kp, for the reaction of SO2and O2to form SO3is 0.365 at 1.15×103K: 2 SO2( g ) + O2( g ) --> 2 SO3( g ) A sample of SO3is introduced into an evacuated container at 1150 K and allowed to dissociate until its partial pressure reaches an equilibrium value of 0.879atm. Calculate the equilibrium partial pressures of SO2and O2in the container.
A reaction vessel contains an equilibrium mixture of SO2, O2,, and SO3. The reaction proceeds such that: 2SO2 (g) + O2 (g) ----> <---- 2SO3 (g) The partial pressures at equilibrium are Pso2=0.001111 atm PO2 = 0.002728 atm PSO3 =0.0166 Calculate the Kp for the reaction.
The equilibrium constant in termso A sample of NOCI is introduced into an evacuated container at 298 K and allowed to dissociate until its partial pressure reaches an equilibrium value of 0.973 atm. Calculate the equilibrium partial pressures of NO and Cl, in the container. atm atm
The equilibrium constant, Kp, for the following reaction is 2.74 at 1.15x103K. 2803(g) 22502(g) + O2(g) + If an equilibrium mixture of the three gases in a 10.9 L container at 1.15*10²K contains SO3 at a pressure of 1.77 atm and SO2 at a pressure of 0.926 atm, the equilibrium partial pressure of O2 is atm.
At 900 K the following reaction has Kp=0.345: 2SO2(g)+O2(g)???2SO3(g) In an equilibrium mixture the partial pressures of SO2 and O2 are 0.150atm and 0.465atm , respectively. What is the equilibrium partial pressure of SO3 in the mixture?
Consider the reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) Kp=2.91×103 at 298 K In a reaction at equilibrium, the partial pressure of SO2 is 0.156 atm and that of Cl2 is 0.365 atm . What is the partial pressure of SO2Cl2 in this mixture?
Assignment 22 Chap 15: Applications of Equilibrium Constants At 900 K the following reaction has Kp=0.345: 2SO2(g)+O2(g)⇌2SO3(g) In an equilibrium mixture, the partial pressures of SO2 and O2 are 0.120 atm and 0.440 atm , respectively. What is the equilibrium partial pressure of SO3 in the mixture?
1- The equilibrium constant, Kc, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) --------> H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and products when 0.395 moles of HI are introduced into a 1.00 L vessel at 698 K. [HI] = M [H2] = M [I2] = M 2- student ran the following reaction in the laboratory at 1090 K: 2SO3(g) ----------> 2SO2(g) + O2(g) When he introduced SO3(g) at a pressure of 1.05 atm into a 1.00...
The equilibrium constant, Kp, for the following reaction is 1.57 at 600 K: CO(g) + Cl2(g) COCl2(g) Calculate the equilibrium partial pressures of all species when CO and Cl2, each at an intitial partial pressure of 1.70 atm, are introduced into an evacuated vessel at 600 K. PCO = atm PCl2 = atm PCOCl2 = atm B. The equilibrium constant, Kc, for the following reaction is 2.90×10-2 at 1150 K. 2SO3(g) 2SO2(g) + O2(g) Calculate Kc at this temperature for...
The squares in the equation are equilibrium signs. The equilibrium constant, Ky, for the following reaction is 0.110 at 298 K: NH_HS(s) NH3(g) + H2S(g) Calculate the equilibrium partial pressure of H2S when 0.416 moles of NH_HS(s) is introduced into a 1.00 L vessel at 298 K. Phys= c atm The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PC15(g) PC13(g) + Cl2(g) Calculate the equilibrium partial pressures of all species when PC15(g) is introduced into...