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The equilibrium constant, Kp, for the following reaction is 2.74 at 1.15x103K. 2803(g) 22502(g) + O2(g)...
The equilibrium constant in terms of pressures, Kp, for the reaction of SO2 and O2 to form SO3 is 0.365 at 1.15×103 K: SO2(g) + O2(g) = 2SO3(g) A sample of SO3 is introduced into an evacuated container at 298 K and allowed to dissociate until its partial pressure reaches an equilibrium value of 0.867 atm. Calculate the equilibrium partial pressures of SO2 and O2 in the container. PSO2 = PO2 =
(1). The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K. 2HI(g) =H2(g) + I2(g) If an equilibrium mixture of the three gases in a 15.5 L container at 698K contains HI at a pressure of 0.399 atm and H2 at a pressure of 0.562 atm, the equilibrium partial pressure of I2 is atm. (2). Consider the following reaction: PCl5(g) =PCl3(g) + Cl2(g) If 1.17×10-3 moles of PCl5, 0.217 moles of PCl3, and 0.351 moles of Cl2 are at...
The equilibrium constant, Kp, for the following reaction is 0.160 at 298K. 2NOBr(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 19.9 L container at 298K contains NOBr at a pressure of 0.297 atm and NO at a pressure of 0.251 atm, the equilibrium partial pressure of Br2 is ? atm.
The equilibrium constant, Kp, for the following reaction is 1.80x10-2 at 698K. 2HI(g) =H2(g) +12(g) If an equilibrium mixture of the three gases in a 14.3 L container at 698K contains HI at a pressure of 1.09 atm and H, at a pressure of 0.929 atm, the equilibrium partial pressure of I, is atm. Submit Answer Retry Entire Group 9 more group attempts remaining
The equilibrium constant in terms of pressures, Kp, for the reaction of SO2and O2to form SO3is 0.365 at 1.15×103K: 2 SO2( g ) + O2( g ) --> 2 SO3( g ) A sample of SO3is introduced into an evacuated container at 1150 K and allowed to dissociate until its partial pressure reaches an equilibrium value of 0.879atm. Calculate the equilibrium partial pressures of SO2and O2in the container.
QUESTION 10 [CLO-6] At 900 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2502 + O2(g) ==== 2503 (g) At equilibrium, the partial pressure of SO2 is 35.0 atm and that of O2 is 15.9 atm. The partial pressure of SO3 is atm 4.21 x 10-3 6.20 x 10-4 82.0 40.2 192
At 900 K the following reaction has Kp=0.345: 2SO2(g)+O2(g)???2SO3(g) In an equilibrium mixture the partial pressures of SO2 and O2 are 0.150atm and 0.465atm , respectively. What is the equilibrium partial pressure of SO3 in the mixture?
A) The equilibrium constant, Kc, for the following reaction is 10.5 at 350K. 2CH2Cl2(g) <->CH4(g) + CCl4(g) If an equilibrium mixture of the three gases in a 19.9 L container at 350K contains 0.416 mol of CH2Cl2(g) and 0.202 mol of CH4, the equilibrium concentration of CCl4 is B) 2SO3(g) <->2SO2(g) + O2(g) If 0.184 moles of SO3(g), 0.477 moles of SO2, and 0.234 moles of O2 are at equilibrium in a 15.0 L container at 1.23×103 K, the value...
At some temperature, the value of the equilibrium constant for the reaction: SO2 (g) + NO2(g) ↔ SO3(g) + NO(g) has the value K = 0.640. If all four gases are placed into a container, each with an initial partial pressure of 1.25 atm, calculate the equilibriuym partial pressure (in atm) of SO3(g)
Assignment 22 Chap 15: Applications of Equilibrium Constants At 900 K the following reaction has Kp=0.345: 2SO2(g)+O2(g)⇌2SO3(g) In an equilibrium mixture, the partial pressures of SO2 and O2 are 0.120 atm and 0.440 atm , respectively. What is the equilibrium partial pressure of SO3 in the mixture?