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If 16.0 grams of aluminum oxide were actually produced, what is the percent yield of the...

If 16.0 grams of aluminum oxide were actually produced, what is the percent yield of the reaction below given that you start with 10.0 g of Al and 19.0 grams of O2? Reaction: 4Al+3O2 yields 2 Al2O3
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Answer #1

4 moles of Al would yield 2 moles of Al2O3
10 g Al is 10/26.98 = 0.3706 moles
You would expect 0.3706/2 moles ( 0.1853 moles) of Al2O3 at 100% yield.
You obtained 16g/101.96 = 0.1569 moles of Al2O3
Your percent yield was 0.1569/0.1853 = 84.7%

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