Homework Answers
10. moles of Cr2O3 = mass / molar mass = 12.2 / 152 = 0.0803 moles
Moles of Al = mass / molar mass = 3.10 / 27 = 0.115 ,oles
From the equation, moles of Al needed to react with all the Cr2O3 = 2 * 0.0803 = 0.161 moles
Since this is more than the moles of Al available, Al is the limiting reagent. Moles of Cr formed = moles of Al reacted = 0.115 moles
Mass of cr = moles * molar mass = 0.115 * 52= 5.98 g
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QUESTION 10 What is the theoretical yield of chromium (Cr) that can be produced by the...
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