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14 Question (1 point) @ See page 289 Chromium(III) oxide reacts with silicon as indicated by the balanced equation below. 2Cr,0, (s) + 3Si(s) — 4Cr(s) + 3Si0, () When 105.0 g Cr2O3 is reacted with 169.0 g Si, it is determined that Cr2O3 is the limiting reagent. 2nd attempt See Periodic Table See Hint If the reaction begins with 105.0 grams of Cr2O3 and 169.0 grams of silicon, how many grams of the excess reactant will be used? g of Si used 12 OF 19 QUESTIONS COMPLETED ) < 14/19 > * VIEW SOLUTION SUBMIT ANSWER

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20120364 35is u crcg+ 3 Si02652 (5) molar mass of Cr₂O3 = 152 gm/mole molar mass of Si = 28gr/mol - Given 105gm Cr₂O3 8 169 gm Si from above reaction it is clear that - 2x152 gm Cr2O3 reacts with 3x28 gm Si so 105 gm Creoz reacts with 3x28x 105 a 2x152 e gom si mass of si used = 29.01 gm ñ 29.0gm si is used a Scanned with CamScanner